Parallel plate capacitor's charge

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SUMMARY

The discussion centers on the calculation of charge in a parallel plate capacitor using the formula E = surface charge density / ε₀. It clarifies that the electric field between the plates is derived from the contributions of both plates, leading to E = surface charge density / ε₀. The confusion arises regarding whether the charge Q should be divided by 2 when calculating the charge on each electrode, as the formula initially accounts for the electric field from both plates. Ultimately, the charge Q represents the charge on one electrode, not the total charge of both electrodes combined.

PREREQUISITES
  • Understanding of electric fields and surface charge density
  • Familiarity with the concept of ε₀ (permittivity of free space)
  • Knowledge of parallel plate capacitor configurations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of electric fields from charged plates in electrostatics
  • Learn about the relationship between charge, area, and electric field in capacitors
  • Explore the concept of capacitance and its formula: C = Q/V
  • Investigate the effects of dielectric materials on parallel plate capacitors
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or capacitor design will benefit from this discussion.

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In this question the charge is calculated by isolating Q in E=surface charge density/absalon not
My question is, the electric field of an infinite charged plane is E=surface charge density/(2*absalon naught)because the electric field in center of parallel plate capacitor are parallel we add

surface charge density/(2*absalon naught)+surface charge density/(2*absalon naught)

to give us E between the electrodes to be surface charge density/absalon notbut when that question uses that formula to find the charge, shouldn't the charge found be divided by 2 to get the charge on each electrode since that formula we initially created by adding the E of both electrodes n this question asks to find charge on each electrode...so what i am really saying is that why isn't the Q in that formula (in that link) charge of both electrodes (their magnitude ofcourse) why is that Q the charge on one electrode?
 
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As you said, the electric field due to one plate is surface charge density/(2*absalon naught) So this is equal to Q/(2A*epsilon naught) (where A is area, and Q is charge on one plate). And the total electric field is twice this (since there are two oppositely charged plates), so it is Q/(A*epsilon naught)
 

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