Recent content by LLS

b = 4(f - 2) + 5 b = 4f - 8 + 5 b = 4f - 13 Thank you

I need to divide by f on both sides. a = -2 and b = 9 Would that make f = 0? And then b = 5? Oy I'm confused. I'll be out for the night at a family dinner in a bit. Please don't be upset if I don't get back to to the problem until tomorrow. I do appreciate the help.

I am having trouble posting a response-getting an error message. I can't quote the above post. "F" is common to both sides. I'm not sure what to do if that is the correct path.

I understand, thank you.

Did I do this one correctly? Homework Statement If a = f - 2 and b = 4f + 5, what is an expression for b in terms of a? It's multiple choice: 4a 4a - 4 4a + 2 4a + 7 4a + 13 The Attempt at a Solution a = f - 2 and b = 4f + 5 add 2 to each side ----> a = f and b = 4f + 7...

Thank you. I've been told that I am an odd person, LOL! :) Have a safe weekend.

Did I do this problem correctly? Homework Statement The √ sign extends over x+3 only. Solve for x. √(x+3) + 3 = 9 The Attempt at a Solution subtract 3 from each side √(x+3) = 6 √(33 + 3) = 6 √36 = 6 x = 33

It's all I have. It might have been easier had the graph been better. Thanx again :)

Would you believe on a wing and a prayer? Wow, I actually got the answer? Finally??!? 2, 2, 2, 2, 2, 2...! Upper right?

Thank you

I came up with 2.

3? I don't think that I am drawing y=x correctly.

I sort of understand that. But I still don't understand what the answer is. How many are there? It seems that the number is infinite.

Yes, at (0,0) I don't understand what you mean by the line y=x. I don't know where to draw it, or how/why it's just one line. I am sorry to confuse you. Things get lost in translation in this format. I'm not getting the concept but I am trying hard.

No worries. I probably didn't phrase it as best as I could have phrased it. I appreciate the help. If I did it correctly, There are 2 points that touch the "S" on each line. I drew lines at (1,1), (2,2), etc and at (0,0). At 0, there are 3. I don't know what the actual number is though. I'm...