Recent content by logan233
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High School A quick Trig Identity Question.
Oh I see now. Thank you.- logan233
- Post #3
- Forum: General Math
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High School A quick Trig Identity Question.
Hopefully this will make sense... We have the trig. identities shown below: sin(u)cos(v) = 0.5[sin(u+v) + sin(u-v)] cos(u)sin(v) = 0.5[sin(u+v) - sin(u-v)] How are these different? I realize u and v switched between the sine and cosine functions, but what is the difference between u and...- logan233
- Thread
- Identity Trig
- Replies: 2
- Forum: General Math
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Open Loop Transfer Function from Differential Equations
Yes. I spent a good amount of time trying to do it on MATLAB/Simulink first, but when I tried it on Excel it was much easier to come up with the integral.- logan233
- Post #17
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
rude man explained it in his posts above very well in my opinion. I don't know if there is anything I can add to any of it that will add to the information. rude man, could you explain what the problem is looking for in Part 3? The problem states, "Simulate open loop control with error in x...- logan233
- Post #13
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
I figured it out using Excel and trapezoidal areas. Thank you for your help.- logan233
- Post #10
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
Okay this all makes perfect sense. I now have clear plots of x_dot vs. t and y_dot vs. t that describe the x and y direction velocities. My problem is now calculating the integrals of these functions. Integrating \dot{x} = Vcos(θ0sin(πt/14)) (as well as the y_dot equation) is proving to...- logan233
- Post #9
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
My new train of thought is this... d(theta)/dt = u -----> d(theta) = u*dt -----> theta = u*t dx/dt = Vcos(theta) -----> dx = Vcos(theta)*dt -----> dx = Vcos(u*t)*dt -----> x = (V/u)*sin(u*t); dy/dt = Vsin(theta) -----> dy = Vsin(theta)*dt -----> dy = Vsin(u*t)*dt -----> y = (V/u) -...- logan233
- Post #7
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
One problem I recognize that I did is integrate x_dot and y_dot incorrectly. x_dot and y_dot are dx/dt and dy/dt respectively, therefore when I integrate I am integrating the left with respect to x (or y) and the right side with respect to t. However, I believe theta is also a function of time...- logan233
- Post #6
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
I didn't state the entire problem because there really isn't much to it. I thought I had a better grasp on it than I apparently do. Here is the entire problem, including the picture used to describe the motion of the car as it switches lanes. I am still unsure of how I would simulate...- logan233
- Post #5
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
Thank you for the reply. I'm actually not sure I'm supposed to find the closed-form transfer functions. The problem statement is kind of vague. I am unclear as to how I would simulate this. Or what I am even simulating. Just thinking about that off the top of my head, I would make a...- logan233
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Open Loop Transfer Function from Differential Equations
Homework Statement Generate an open loop u(t) and simulate. Plot x(t) and y(t) \dot{x} = Vcos(θ) \dot{y} = Vsin(θ) \dot{θ} = u I am given initial values. All are 0 except for \dot{x}(0) = V. Homework Equations Laplace Transform Tables The Attempt at a Solution I think I...- logan233
- Thread
- Differential Differential equations Function Loop Transfer function
- Replies: 18
- Forum: Engineering and Comp Sci Homework Help