Recent content by Loke

but when i use thevenin theorem much more easier !

Thanks ~~~~ i got it ^^

oh i got it already! find the total V and then find for I3 :))

u meant RN parallel with R3 parallel with R25 and parallel with current source ?

ermmm ...then what should i do next in order to get I3=1.29A ? oh the second pic is the correct 1 ~?

ermmm..i don't know how to solve the lefthand piece with its norton equivalent...In=R25 ?

yes... that's how i do in the beginning ...IN=V14/R14=20/7=2.855A ...but why i still can't get 1.29A ...

mind if i see how you work it out the solution? i uploaded the pic...but if i shorted the R3 ...then i don't know how to proceed.

as for norton theorem approach, i shorted R3 and i get IN=V14/R14=V25/R14=20/7=2.855A i still got the same answer...and how to find RN when i open R3 and shorted voltage source ...R1+R2+R4+R5=17ohm ? how about Rtotal...when you short the R3 ...Rtotal also = 17ohm?

by the way, can you show me your solution? actually this is not my homework... i just want to know how to do...because i almost exam...i just simply find a question and do...or at least tell me your answer...i work it out myself...i really running out of time...no offence...thanks...

Ohh... in my kirchhoff's law equation, my I2 is flowing through resistor R3 and i get I2 equal to -1.29A not I3=0.645A i wrote wrongly ...whereas in my norton theorem equation, my I3 flowing through resistor R3...which is IN=2.855A...the answer is not the same...please advice.

attempt solution: -norton theorem IN=VS/(R1+R4)=2.86A -kirchhoff's law 20-2I1-5I1-5I2=0 5I3+5I3-5I2=0 I1=I2+I3

Find the current in I3 resistor by using kirchhoff's laws. problems: -when i try to use norton theorem to check for my answer and my answer is IN=2.855A=I3 but when i use kirchhoff's law i get I3=0.645A. -i don't know where is the problems...the current for norton theorem and kirchhoff's...

Is my attempt solution correct? oh i know ady...thanks karthick...^^ my answer is wrong.Should be V=11.78v

Find the the equivalent Thevenin’s Voltage (VTH) across resistor R3 for the circuit. -can anyone tell me what's your answer for the solution? -if i want to use current divider rule...how am i going to solve it? attempt solution: Vth=VR3=R3/(R1+R3+R2)*V = 8.33v