Find Thevenin's Voltage (VTH) Across Resistor R3 - Thevenin Theorem

  • Thread starter Thread starter Loke
  • Start date Start date
  • Tags Tags
    Theorem Thevenin
Loke
Messages
27
Reaction score
0
Find the the equivalent Thevenin’s Voltage (VTH) across resistor R3 for the circuit.

-can anyone tell me what's your answer for the solution?
-if i want to use current divider rule...how am i going to solve it?

attempt solution:
Vth=VR3=R3/(R1+R3+R2)*V
= 8.33v
 

Attachments

  • 1.jpg
    1.jpg
    8.5 KB · Views: 463
Last edited:
Physics news on Phys.org
To find Thevenin voltage across R3, remove R3 from the circuit. Find current flowing in the circuit and from this find voltage drop across all resistors. Now find voltage difference across the points where R3 was present. That will give you the Thevenin voltage across R3.
 
Is my attempt solution correct? oh i know ady...thanks karthick...^^ my answer is wrong.Should be V=11.78v
 
Last edited:
Yes your answer is right, it is 11.7V
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top