Consider the ODE
dy/dx + 0.6y = 0.5e^(-(1.1)x) , y(0) = 4
solve the ODE subject to the given condition using exact methods and evaluate the solution y for x = 0.0 (0.05) 0.5, (i.e from x = 0 to x = 0.5 in steps of 0.05)
I am terrible with ODEs and would greatly appreciate help in...
setting a sinusoidal voltage term, the ODE can be written as
(d^2 i)/(d t^2 ) + 25i = A0 sin (ϖt)
assuming that ϖ^2 ≠ 25, determine the current i in terms of the parameters (ϖ and A0) and the variable t when the initial conditions are
i(0) = di/dt (0) = 0
i really don't have much of...
no i don't know where to start with the graph. I am guessing that the graph is to take the shape of a saw tooth, could be wrong though. i also do not understand what the (x+1) (x-1) stands for
A periodic function f(x) has period 2 and is defined as
f(x) = -2.4 (x+1) ,-1 ≤ x < 0
2.4 (1-x) , 0 < x ≤ 1
with f(x+2) = f(x) for all x
sketch the graph of f(x) over the interval (-4, +4) and determine the Fourier coefficient Ao.
I really don't know where to start with this...
Could someone please look over this question
d^2i/dt^2 + 25i = 0
where i(0) =15 and di/dt(0) = 0
sketch the graph of i against t(t>0) over 2 cycles
attempt:
General Solution
i=Acos(5t) + Bsin(5t)
when i(0) = 15 is applied
A = 15
P.S
ip= Acos(5t) + Bcos(5t)
ip'= -5Asin(5t) +...