I believe the equation to find Initial velocity is,
Vo = V - AT
But I forgot what is V.
From what I remember, I think V = Vf - Vo isn't it? So if I don't know neither Vo and Vf, how can I calculate V?
And the equation for final velocity is (Vf)^2 = (Vo)^2 + 2aΔx.
To find distance:
Δx = V0Δt + .5a (Δt) 2
Δx =?
V0 = 0 m/s
Δt = 5 s
A = 5.3 m/s 2
Δx = 0 m/s (5s) + .5 (-5.3 m/s 2) (5s) 2
Δx = 0 m + 2.65m/s 2 (25s 2)
Δx = 0 m + 2.65m/s 2 (25s 2)
Δx = 0 m + 66.25 m
Δx = 66.25 m
I use this method to find Vo, however, Vo comes out to be 0.
Δx =...
For the 1st part, I'm not really sure is it correct.
The acceleration I plug in is -9.8 m/s ^ 2, but shouldn't it be -5.3m/s ^ 2?
Also for the 1st part, the answer I got is negative. But is correct to have a negative height?
For the three version you mentioned, are the following the right approaches?
If this is the right way, how do I find Vo
Δx = V0Δt + .5a(Δt)2
Δx =?
V0 =
Δt = 5 s
A = 5.3 m/s 2
Same thing, if this is the right approach, how do I find Vo
Δx = V0Δt + .5a(Δt)2
Δx =?
V0 =?
Δt = 64 s
A = 5.3 m/s 2...
Homework Statement
A train left the station by accelerating at 5.3 m/s 2 for 5 seconds. It then continued at constant speed for 64 seconds. As it approached the next station, it slowed to a stop at 4.2 m/s 2.
What is the distance between the 2 stations?
Homework Equations
Δx = V0Δt...
1. Marcia was driving her car at the constant speed of 19.2 m/s when she saw the light turn red. It took her .13 sec to hit the brakes, but then the car slowed at the constant rate of 6.2 m/s2 until it stopped. How much time did it take for the car to stop moving after the light turned red.? How...