Recent content by louis676

Yes I understand.. Thank you!

I know why I need to find Initial velocity, but why do I need to find final velocity?

Alright Thanks.

I believe the equation to find Initial velocity is, Vo = V - AT But I forgot what is V. From what I remember, I think V = Vf - Vo isn't it? So if I don't know neither Vo and Vf, how can I calculate V? And the equation for final velocity is (Vf)^2 = (Vo)^2 + 2aΔx.

To find distance: Δx = V0Δt + .5a (Δt) 2 Δx =? V0 = 0 m/s Δt = 5 s A = 5.3 m/s 2 Δx = 0 m/s (5s) + .5 (-5.3 m/s 2) (5s) 2 Δx = 0 m + 2.65m/s 2 (25s 2) Δx = 0 m + 2.65m/s 2 (25s 2) Δx = 0 m + 66.25 m Δx = 66.25 m I use this method to find Vo, however, Vo comes out to be 0. Δx =...

For the 1st part, I'm not really sure is it correct. The acceleration I plug in is -9.8 m/s ^ 2, but shouldn't it be -5.3m/s ^ 2? Also for the 1st part, the answer I got is negative. But is correct to have a negative height?

Is this correct? 1s part Δx = V0Δt + .5a (Δt) 2 Δx =? V0 = 0 m/s Δt = 5 s A = 5.3 m/s 2 Δx = 0 m/s (5s) + .5 (-9.8m/s 2) (5s) 2 Δx = 122.5 2nd part Δx = V0Δt + .5a (Δt) 2 Δx =122.5 V0 =? Δt = 64 s A = 5.3 m/s 2 Δx = V0Δt + .5a (Δt) 2 122.5 m= VO (64s) + .5 (-9.8 m/s 2)...

I'm not really good with graph lol.. I know using graph is easier to find answer, but my teacher insist to use equation.

For the three version you mentioned, are the following the right approaches? If this is the right way, how do I find Vo Δx = V0Δt + .5a(Δt)2 Δx =? V0 = Δt = 5 s A = 5.3 m/s 2 Same thing, if this is the right approach, how do I find Vo Δx = V0Δt + .5a(Δt)2 Δx =? V0 =? Δt = 64 s A = 5.3 m/s 2...

Homework Statement A train left the station by accelerating at 5.3 m/s 2 for 5 seconds. It then continued at constant speed for 64 seconds. As it approached the next station, it slowed to a stop at 4.2 m/s 2. What is the distance between the 2 stations? Homework Equations Δx = V0Δt...

Bump!

1. Marcia was driving her car at the constant speed of 19.2 m/s when she saw the light turn red. It took her .13 sec to hit the brakes, but then the car slowed at the constant rate of 6.2 m/s2 until it stopped. How much time did it take for the car to stop moving after the light turned red.? How...

Opps lol! Thank you so much for your help Berkeman..Appreciate all the time you help me

Alrite thank you so much.

So my answer is correct, right?