thanks! :}
guys ye don't know how much ye've actually just helped me and now that i go over wat ye said it seems very clear! i think iv got it ;} right so it goes:
m*vsrd/d=GMm/dsqrd where d is moon orbital radius so vsqrd is GM/d.
then time T=2pid/v. make t a squared, sub in v squared end...
i don't understand how Earth's radius and gravity come into it. centripetal acceleration is equal to the force of gravitational attraction. the equations say its at the height or distance of the moons orbit d.
m*v squared/r =GMm/d squared. d is the distance of moons orbit from centre of earth...
how is force equal to mass by distance by 4 pi squared all over period squared.i should prob know :{ i think i may be more lost than i thought. thanks for the equations i'l be back if i make progress! il read the chapterinside oput again.
The question: assuming that the moon circles the Earth in an orbit of radius d show thatthe periodic time T of the moon may be expressed as: T=2pi d sqrt d/r sqrt g where r is the radius of Earth and g is acceleration due to gravity on Earth's surface
i took up physics 2 to 3 months ago on...