Recent content by LP20

Homework Statement Find Voltage V_0. There is also a dependent voltage source in the circuit I'm not sure what to do with. The two nodes on top are essential nodes and can be treated as one, same with both bottom nodes, but the bottom nodes I assigned them to be the reference node. Picture...

That is exactly what it is saying, your resultant force is 100lb above B 45". This moment equals all the other moments acting on the beam from the other forces. Just like summing up the forces, your summing up the moments. No problem for the help. I've been helped many times on here before...

It should be. Do you have an answer for it in the book? I got an answer that seems reasonable. What's yours?

Hi there, Now I remember only a little bit from my statics class, but you did find fx correctly. Now for the height. Moments are the correct way to do it, I would suggest to find the total for all moments and see where you can go from there. Once you get that, think of the moment formula...

Homework Statement We are given currents ia and ib, 4A and 2A respectively. We must find ig and vg (tough). I understand how to do b and d easily once I get the unknowns (ig and vg), that's what I need help with.Picture > http://img210.imageshack.us/img210/3667/1000943d.jpg The Attempt at a...

I understand it now! finally, took a full day though. I got 20 ohms for total resistance, than I did find the rest from that, using kvl's. Thanks for helping me out!

hey wait a sec. Couldn't I find what r equals is and then solve for the current ia? It would be : r(equal)= 24ohms. Voltage =50v so i=v/r would be i= 50/24 = 2.08. Would this be allowed to find the current ia ? the answer in the book is 2 A.

oh ok. I believe I understand what your saying. Except I'm looking though all my notes and my book like crazy to find the part about 0v for ground and it doesn't look like we have learned it yet. No worries though, with this knowledge I will try to solve or get more equations now then solve. I...

Would the voltage be 50v? that's the only voltage source but doesn't voltage change once passed through a resistor? or would the voltage be unknown making this equation v=20ia? Maybe I'm over thinking things. I feel half retarded lol. I know there is just something I'm not understanding about this.

ok thanks! maybe it's the circuit theory I'm still having trouble with. If I try to make an equation for Ia : (i=v/r) which voltage would I use? would it be the one from the source or the one from the 4 ohm branch? or would it be a totally different voltage? i=v?/20

Homework Statement Given the circuit shown find: a) value of i_a b) value of i_b c) value of V_o d) power dissipated in each resistor e) power delivered by the 50v source Picture: (http://img197.imageshack.us/img197/4515/1000941y.jpg ) I am very new to circuits, any help would be...

Alright nvn, I think I know how to do it, I already turned in my assignment today. We actually had a test on moments too. It went very smoothly. But I'll probably be back asking more questions in the future. Thanks!

WEll, Tomorrow this assignment is due, but no worries. I would still LOVE to figure this one out, its seems so simple yet its killing me on the inside. So The Magnitude of the equivalent force is -48N. And I thought the line of action is where the force follows the direction its pointing...

ok, so vertial force would be -48 N and horizontal would be 0 N. Alrighty, Thus the line of action would be on BC. Ok so what about part b). If line of action was 300mm to the right of point d? Wouldn't alpha be the same as it is now, just because it's part of a couple force and it produces...

But, this is exactly what I don't get. Do I add force components from the force and the couple force together? Wouldn't the couple forces just cancel out, so you'd be left with 48 n? Any other hints would help.