Node-Voltage help. Is my equation right?

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SUMMARY

The discussion focuses on solving for the voltage V_0 in a circuit with a dependent voltage source. The node voltage equation presented is -3 + V/200 + (V-5i)/10 + (V -80)/20, where V represents V_0 and i denotes the dependent current i_Δ. The key takeaway is the importance of applying Kirchhoff's Current Law (KCL) to analyze the circuit, particularly by considering the sum of currents at the essential nodes without overcomplicating the process with voltage references.

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Homework Statement


Find Voltage V_0. There is also a dependent voltage source in the circuit I'm not sure what to do with.
The two nodes on top are essential nodes and can be treated as one, same with both bottom nodes, but the bottom nodes I assigned them to be the reference node.

Picture: http://img696.imageshack.us/img696/5396/1000948x.jpg

Homework Equations


The Attempt at a Solution


My node voltage equation : -3 + V/200 + (V-5i)/10 + (V -80)/20
V is V sub 0: V_0
and i is i sub delta i_Δ

For the equation for i_Δ : would it be (v-80)/20

Again I'm unsure of how to handle the dependent source in this circuit.
 
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LP20 said:

Homework Statement


Find Voltage V_0. There is also a dependent voltage source in the circuit I'm not sure what to do with.
The two nodes on top are essential nodes and can be treated as one, same with both bottom nodes, but the bottom nodes I assigned them to be the reference node.

Picture: http://img696.imageshack.us/img696/5396/1000948x.jpg


Homework Equations





The Attempt at a Solution


My node voltage equation : -3 + V/200 + (V-5i)/10 + (V -80)/20
V is V sub 0: V_0
and i is i sub delta i_Δ

For the equation for i_Δ : would it be (v-80)/20

Again I'm unsure of how to handle the dependent source in this circuit.

There really is only one KCL equation for that circuit. You write the sum of all the currents leaving (or entering) the node at the upper left of the circuit (you are correct to call the bottom node the reference or ground node). Don't over-think this -- keep thinking currents. So for the right-hand leg, what is the current leaving out that way? Hint: No voltages are involved. Alternately, you can write i_Δ in terms of V_o and constants...
 
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