Recent content by lpau001

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    Using Induction to prove something false?

    Howdy, I am clumsy at best with induction (pretty new to it sadly), and I was wondering if it's proper to prove something false with induction? Every time I've used induction it's always been to prove something true. It may be a dumb question, but I'm beginning to think induction is only for...
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    Linear Gradient Series Derivation

    The formula I was given in class was derived like this: You have a set of N payments of amount A. The sum of these payments is symmetrical to a geometric progression sum. a + ax + ax^{2} + ... + ax^{N-1} = \frac{a(x^{n}-1)}{x-1} if you let x=(1+i) Then F=A\frac{(1+i)^{N}-1}{i}...
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    Linear Gradient Series Derivation

    Ray, Thank you very much! I have used Wolfram Alpha before, but never to such an extent. Very cool. I did have a quick question though, on your previous formula, where you have : PV1 = A + Aρ + Aρ^{2} + ... + Aρ^{N} = A\frac{1-ρ^{N+1}}{1-ρ} Where ρ=\frac{1}{1+i} How did you...
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    Linear Gradient Series Derivation

    Hmm.. ok! So if I don't have any of those fancy things, just 'guess and check' is as viable as anything? Thanks for your help Ray.
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    Linear Gradient Series Derivation

    This may sound dumb, but how do I solve for N when it is a normal variable AND an exponent? .. I'm totally baffled.
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    Linear Gradient Series Derivation

    (1) F=P(1+i)^{N} (2) F=A \frac{(1+i)^{N}-1}{i} (2) is derived from F = A(1+i)^{0} + A(1+i)^{1} + A(1+i)^{2} A(1+i)^{3} + ... + A(1+i)^{N-1} = A \frac{(1+i)^{N}-1}{1+i-1} using (1) and (2) to solve for P gets the formula.
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    Linear Gradient Series Derivation

    Well that's the problem. I found this formula online, but I was hoping someone could show me the actual steps to get to this formula so I could understand it?
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    Linear Gradient Series Derivation

    Howdy, I guess I need to explain this situation a little bit.. I am doing a project about a guy buying a house, but using a gradient series approach to do the payments, for example, say the original monthly payment for a $225,000 15 year loan is ~$1600. The guy will pay that the first month, and...
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    Pure Recursive Function for f(n) = 6[SUP]n[/SUP] + 6n

    Wow.. Simply Amazing! I really need to work more on using the function to help me out, instead of just trying to figure out how the function works! You really made this problem look easy! Thank you very much!
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    Pure Recursive Function for f(n) = 6[SUP]n[/SUP] + 6n

    "Pure Recursive Function" for f(n) = 6n + 6n Howdy! First of all I was going to explain a 'Pure Recursive Function' as how my professor defined it: A pure recursive function is stated by only using previous values of the function.. Like: F(n) = f(n-1) + f(n-2) Which means you can't have a...
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    Proving \exists x \in (1, \infty): xy\geq1

    Ok, I'm with you on this so far, but what value would I use for 'y' when you say "...relative to the value of y*x0?" In my head, y0 and y are the same thing.. you know what I mean? I'm just super lost.. I'm looking at the graph, and I can see that the interval (0,y0) would be decreasing...
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    Proving \exists x \in (1, \infty): xy\geq1

    Hmm.. I am trying hard to understand what you're trying to tell me, but it's slipping me.. I understand that there is one y value (y*) for every x, to make xy*=1 .. The y* value divides the interval into 2 pieces. y* gets increasingly smaller as x gets bigger.. Is that what you were asking...
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    Proving \exists x \in (1, \infty): xy\geq1

    Hey! I tried to make the title as descriptive as possible, but ran out of characters. I am trying to prove that.. Homework Statement "There exists x \in (1, \infty) such that for all y \in (0,1), xy\geq1. \exists x \in (1, \infty) s.t. \forall y \in (0,1), xy\geq1. Homework...
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    Solving a Virtual Image Problem Involving a Converging Lens

    Homework Statement A converging lens of focal length 0.246 m forms a virtual image of an object. The image appears to be .933 m from the lens on the same side as the object. What is the distance between the object and the lens? Homework Equations 1/f = 1/di + 1/do Since the image is...
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    Calculating Impedance in an RLC circuit

    I actually did try this in an earlier attempt, because I thought this was right, but apparently not. 1/Z=1/Zr + 1/Zx I'm stuck, and I actually ran out of attempts on the HW, but this is more out of curiosity now than anything. Thanks, Gneill
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