Recent content by Lucas_30

Right! Thanks again.

Hi DrClaude, Oh, yes! I did mix this up. 1/2(-2)t^2... so the coefficient should be 1/2(-2)...

Hi DrClaude, There was a problem with the image I used - I have updated the text so it should make sense now. Yes, you're right in that they are equivalent, but I wanted to know why the latter suited the problem better than the first. I suppose in terms of problem solving I wanted to...

Hi DrClaude, I "solved" it using the quadratic equation: https://www.symbolab.com/solver/equation-calculator/\frac{ 5 - \sqrt{5^{2} - \left(4\right)\left(-2\right)\left(6\right)}}{2 \left(-2\right)} https://www.symbolab.com/solver/equation-calculator/\frac{ 5 + \sqrt{5^{2} -...

Hello everyone, this is my first post, so go easy on me! Thank you to those who are able to help. 1. Homework Statement The problem is taken from Professor Shankar's Fundamentals of Physics exercises (Problem 3). Romeo is at x = 0 m at t = 0 s when he sees Juliet at x = 6 m Romeo begins...