Recent content by ludic

I thank you both profoundly for your patient and analytical explanations.

Please be so kind and patient to clarify this doubt: I understand the part where mercury in column becomes heavier and goes down because of increased effective acceleration What I don't understand is why - if we call the pressure of atmosphere it's weight upon unit surface area being...

Please be so kind and patient to clarify this doubt: I understand the part where mercury in column becomes heavier and goes down because of increased effective acceleration What I don't understand is why - if we call the pressure of atmosphere it's weight upon unit surface area being...

Please once say that it will. I need to cite this thread somewhere... please...

But why would we assume it otherwise ? And my answer and explanation are sound if the air in the surrounding is not confined as in the elevator, right?

so, am I right ? Will the height remain same ?

I do think so. ... because: Mg / A = h(rho)g ---------------- static condition M(g+a) / A = h'(rho)(g+a) ------------ accelerating condition. ergo, h' = h where rho is the density of mercury and M is the mass of the...

yes... now i come to think of it, it will... so, will the height of mercury in the column remain same ?

What would happen to the mercury in the column if a barometer is accelerated upwards? In static condition, acceleration is g. When the system moves upward with an acceleration a, effective acceleration = g + a. The air above the mercury in the trough will press it with higher force...

What would happen to the mercury in the column if a barometer is accelerated upwards? In static condition, acceleration is g. When the system moves upward with an acceleration a, effective acceleration = g + a. The air above the mercury in the trough will press it with higher force...

A bike starts from rest. It covers a distance of 1km from rest to rest. If the minimum time in which the bike covers the distance is 100s, the coefficient of friction between road and tyre = ? s = (1/2)at^2 no idea how to go about it.