Recent content by Luminous Blob

Just delete the root folder and all its subfolders, as explained here: http://cygwin.com/faq/faq_2.html#SEC20

Hmm, I loved King's Quest, Space Quest and Police Quest. My favourite games were probably Wizardry - Proving Grounds Of The Mad Overlord and Starflight I and II. Then there was Elite, which was awesome too.

Is there a particular language that the program is to be written in?

How old is this computer? Is Windows 2000 already installed on it, or are you trying to install Windows 2000 on it and having trouble completing the install?

Okay, well I'm pretty sure that's a router. The site you linked seems to have a page for that one, so try this and see if it helps: http://portforward.com/english/routers/port_forwarding/Westell/Westell6100/Utorrent.htm

Okay, if you're not behind a router and you're using Windows Firewall, then that list isn't going to help, because they're all routers and hardware firewalls. What brand and model of modem are you using?

By that do you mean which router should you choose out of the list on the site you linked?

Haha, I see now...as you may have noticed, I'm not exactly the sharpest tool in the shed :) Thanks again.

Hang on, after looking at it a bit more I'm not so sure...wouldn't that give you a factor of 2 out the front rather than 1/2?

Ah, gotcha! Thanks :)

I'm trying to follow a derivation in given in a textbook. Part of this derivation goes like this: \frac{d}{ds}\left(\frac{1}{c}\frac{dx}{ds}\right)=c\left(\frac{\partial^2\tau}{\partial x^2}\frac{\partial \tau}{\partial x} + \frac{\partial^2\tau}{\partial x \partial y}\frac{\partial...

Right then, setting the integrand to zero: e^{-i\omega t} \left( \nabla^2 \tilde{\psi}\left( x,y,z,\omega \right) + c^{-2} \omega^2 \tilde{\psi} \left( x,y,z,\omega \right) \right) = 0 Which gives \nabla^2\tilde{\psi}+\frac{\omega^2 \tilde{\psi}}{c^2}=0 which is...the Helmholtz equation...

After doing that, you get \frac{1}{2 \pi}\int_{-\infty}^{\infty}e^{-i\omega t} \left( \nabla^2 \tilde{\psi}\left( x,y,z,\omega \right) + c^{-2} \omega^2 \tilde{\psi} \left( x,y,z,\omega \right) \right)d\omega=0 ?

So it'd look like this after the substitution? \frac{1}{2 \pi}\int_{-\infty}^{\infty}\nabla^2 \tilde{\psi}\left( x,y,z,\omega \right) e^{-i\omega t}d\omega -c^{-2}\frac{1}{2 \pi} \int_{-\infty}^{\infty} \frac{\partial^2}{\partial t^2} \left[ \tilde{\psi} \left( x,y,z,\omega \right)...

So, wherever \psi appears in the original wave equation, it is replaced by \frac{1}{2\pi} \int_{-\infty}^{\infty} \tilde{\psi} \left( x,y,z,\omega \right) e^{-i\omega t}dt ? Also, what do you mean by "assume that you can move partial derivatives through the integral signs"? Thanks...