Recent content by MadMcB

Homework Statement 2 cables are used to support a 24kg mass on a 1.6m long, 8kg uniform horizontal beam. The 24kg mass is 0.6m from the right cable. What is the tension in the right cable? Homework Equations torque = rFsinx The Attempt at a Solution Fy = ma = 24(9.8) = 235.2N Fx = ...

Okay, so then the vertical components are 0.49N. That means the force of friction by the floor is 0.49 N in the opposite direction?

How do I get the separate vertical components then? Since the mass is uniform, do I just divide 0.98 by 2 to get 0.49N?

Okay, I must be really confused. I thought 0.98N was the vertical components?

The net forces? or are you talking about the horizontal components?

Okay. So the gravitational force, or the normal force is 0.98m. If the stick isn't moving, that means the force acting upwards on the stick is 0.98m as well?

Okay. So how would I find the horizontal and vertical components of the force at the top of the stick?

Thanks Bystander. So to find a coefficient of static friction, my formula would by Fsf = u(static)Fn. I know the normal force is 0.98N, but I don't know how to find either the coefficient or force of friction from here. What should I try next?

Homework Statement Please see attached picture. Homework Equations Ff=uFn[/B]The Attempt at a Solution I'm really not sure where to start, since I don't know the coefficient of friction. Fn = ma Fn = 0.1kg(9.8m/s^2) Fn = 0.98N Does this mean that the force in the image is 0.98N as well...

Thanks for your help.

65˚ from the horizontal. So the tension is sin65˚ = o/h = 49/h. So h = 49/sin65 = 54.07 N using pythagorean's theorem: x^2 + 49^2 = 54.07^2. So x^2 = 522.56, and x = 22.86 N So, F = 23N. Is this correct?

here you go! Apologies- It is sideways

Can I insert an image as a file from my computer??

Thanks Brain. How do I know the net force? If I had the net force and the vertical component, I could solve for the horizontal component...

Hi TSny! Thanks for the advice. I've drawn a diagram, and I know that the vertical component of the normal force on the object is 49N. How do I find the vertical component?