Yes we are allowed to look up the specific heats. For aluminum Ca is 0.900 J/gK and for water, Cw is 4.184 J/gK. However, plugging these into my original equation still leaves Tiw and Tf unknown
As the entropy of the system is changing, the only thing that I could think of that would be conserved is energy. The first law of thermodynamics states that ΔU=W+Q where U is the internal energy. Also the equation relating T,U, and s is 1/T=Δs/ΔU. I'm not quite sure how I would use these two to...
Homework Statement
I am Pretty Lost with this problem...[/B]
A 2.45-kg aluminum pan at 155∘C is plunged into 3.58 kg of water. If the entropy change of the system is 162 J/K, what was the initial temperature of the water? NOTE:We did not receive a Tf for the system.
Homework Equations...