I had another go at it, this is as far as I got:
Thanks so far btw! :)
A mass of 2 kg is dropped vertically into a frictionless slide located in the x-y plane. The mass enters with zero velocity at (-5,5) and exits traveling horizontally at (0,0).
Assuming the slide to be perfectly...
I can't find anything on the internet about this...
How is it done?
I've got a smooth curve given by these parametric equations:
y = 5cos( theta )+5; x = 5sin( theta )
taking g = 9.81
how can I model the position of the ball as a function of time?
Or how can I model it so that i can...
ok, so the parametric equation for a circle radius 5 origin 0,5 is
y = 5cos( \theta )+5; x = 5sin( \theta )
or in Cartesian form
(x)^2 + (y-5)^2 = 25
would the velocity at any given y be
v^2 = 2 g (y-5)
or would that just be the y component of the velocity?