Recent content by MareMaris

In the end after substituting everything in I got -pi/2root(1+x)

In the end to get sin(t) and cos(t) in terms of u I just drew a right angle triangle with the side opposite to the hypotenuse as u and the side adjacent to it as 1, and worked it out using trig, seemed easier than using the identities and double angle rules that potentially you have to use...

Hmm, I had a go at that but I'm still left with this sin^2(t) which I'm not sure how to get rid of, I tried changing it to 1-(cos^t) and tried linking that to dx/du which is cos^2(t) but no joy so far!

Homework Statement Integrate -1/(1+x(sin(t))^2) between 0 and pi/2 using the substitution u = tan(t)The Attempt at a Solution du/dt = (sec(t))^2 dt/du = 1/(1+u^2) I've messed around with the integral and trig. identities but I don't seem to be getting anywhere changing the integral to make...