Recent content by markdflip

Thanks for the help. I need to fix my habit of not writing labels with constants since I just get used to them cancelling out. I replaced the specific energy wof ice with 2050 instead of 2000, and used the correct value of latent heat at 335000 and got 16.03, the correct answer. Thank you...

oh, that was in J/g...so that would be 333,550 J/Kg That makes more sense, 674,500J would be left for the third step opposed to 4,006,665J 674,500J/(10*4184)=deltaT DeltaT=16.12 degrees Celsius. Sound realistic?

Homework Statement A 10 kg block of ice has a temperature of -8°C. The pressure is one atmosphere. The block absorbs 4.17 x10^6 J of heat. What is the final temperature of the liquid water? Q=4.17x10^6J T_0=-8 Mass=10kg 4184= specific heat of water 2000=specific heat of ice...