Recent content by marpple

yup.,, got it.. thanks :)

6 U_0 but, then i guess E = 6 U_0 is for K x > L

k = e - u_0 = u_0 ?

e=k + u

Homework Statement The potential-energy function U(x) has the constant value U_0 in the interval 0 < x < L and is zero outside this interval. An electron is moving past this square barrier, but the energy of the electron is greater than the barrier height. If E= 6 U_0, what is the ratio...

omg..i'm still thinking that it goes from air to prism.. LOL

for the first wavelength.. na sin 58 = n1 sin 70 n1 = (sin 58 . 1 ) / sin 70 = 0.902 for the scond wavelength... na sin 58 = n2 sin 78.5 n2 = (sin 58 . 1 ) / sin 78.5 = 0.865 actually, I'm not so sure about which one is the first wave and which one is the second. so, here i...

Find the index of refraction of the prism for each of the two wavelengths. n1 = 0.902 and n2 = 0.865

noooo... it's still wrong :cry:

well, let me try again :biggrin: for the first wavelength the angle of incidence is 58 degree, and the angle of refraction is 70 ?? for the second wavelength the angle of incidence is 58 degree, and the angle of refraction is 78.5 ??

LOL... how did you know?? :shy: ic,, i'll work on it :)

LOL :biggrin: ic,,is this because i took the normal wrongly..??

which one is not correct?? the angle of the incidence or the angle of refraction??

so, for the first wavelength the angle of incidence is 32 degree, and the angle of refraction is 12 ?? for the second wavelength the angle of incidence is 32 degree, and the angle of refraction is 20.5 ?? am i on the right track??

ahh..i thought it was total internal reflection since the ray coming in 90 degree,, but.. for total internal reflection 90 degree should be for the angle of refraction. :biggrin: so, we don't need to consider from air to glass? yess...yess... blame mastering physics :wink: