Recent content by Martin

  1. M

    What Do F=ma and the Definitions of Force and Mass Really Mean?

    But their definitions do not come from this equation. The equation simply expresses how they are related through a. Physics, and virtually every other field of science, ultimately rests upon a small set of basic concepts that are taken as virtually self-evident (similar to axioms in...
  2. M

    Differential by another differential

    See if this helps: http://web.mit.edu/wwmath/calculus/differentiation/products.html"
  3. M

    Where Did Half the Energy of Two Capacitors Go?

    Lumped circuit theory assumes that all electrical effects happen instantaneously throughout the circuit, which is approximately realized if the dimensions of the circuit are small compared to the wavelength. This assumption is equivalent to ignoring the finite velocity of electromagnetic field...
  4. M

    Where Did Half the Energy of Two Capacitors Go?

    I said: “Lumped circuit theory is valid in the sense that it provides useful approximate results whose accuracy depends upon the degree to which its underlying assumptions and restrictions are met in any particular application.” Inherent to the theory’s applicability is the assumption that...
  5. M

    Where Did Half the Energy of Two Capacitors Go?

    See my previous post.
  6. M

    Where Did Half the Energy of Two Capacitors Go?

    Lumped circuit theory is valid in the sense that it provides useful approximate results whose accuracy depends upon the degree to which its underlying assumptions and restrictions are met in any particular application. When I commented on its validity, I said strictly speaking it was not valid...
  7. M

    Where Did Half the Energy of Two Capacitors Go?

    Lumped circuit theory is a self-consistent model that approximates real circuits. There are a number of assumptions inherent in lumped circuit theory that do not hold 100% in “real” circuits. How well the theory models the actual behavior of any “real” circuit will depend upon how closely those...
  8. M

    Where Did Half the Energy of Two Capacitors Go?

    I would, if only I knew what you were referring to. :confused: :wink:
  9. M

    Where Did Half the Energy of Two Capacitors Go?

    No. The energy is dissipated in the zero resistance of the wires: The circuit responds to the closing of the switch by producing an impulse of current—which is a current of infinite magnitude lasting zero time, such that the charge transferred from the 1st capacitor to the second capacitor (the...
  10. M

    Where Did Half the Energy of Two Capacitors Go?

    After the switch is closed, both capacitors must have the same voltage. Since the relationship between charge and voltage for an ideal capacitor is given by charge = capacitance X voltage, and since the capacitors are the same size and have the same voltage, they must have the same charge. And...
  11. M

    Where Did Half the Energy of Two Capacitors Go?

    As I suggested above, go through the analysis that Reality_Patrol performed: Insert a series resistance R in the circuit, and do the math. You will find, as Reality_Patrol found, that the total energy dissipated by R is (1/4) (1/C) X Q^2, independent of the value of R. The resistance does affect...
  12. M

    Where Did Half the Energy of Two Capacitors Go?

    Why not? “Infinity times zero” can very well be finite—you yourself realized that when you noted that: Go through the analysis that Reality_Patrol performed: Insert a series resistance R in the circuit. Calculate the current, power, and, finally, the energy dissipated by the resistance from...
  13. M

    Where Did Half the Energy of Two Capacitors Go?

    If the result of my “just being difficult” was to get you to expend a little bit of effort thinking through the problem, then perhaps my “just being difficult” isn’t such a bad thing. :wink: That is (seemingly) counter intuitive, don’t you think? There you go, complaining again! :wink: You...
  14. M

    Where Did Half the Energy of Two Capacitors Go?

    You are correct, and on the right track to solving the problem.
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