Recent content by masterburn

I'm not sure what way to approach ? it was the only way I was taught ? the only thing i know following your logic is density avg > density fluid since it only half sunk, so the free diagram is mg going down and fb going up then it would be Fb>mg, how so i have buoyancy force of FB but i think it...

no i cannot continue from there not sure how ? since half the block is submerged and, the volume displaced is the amount from the submerged block therefore density unknown = h of block/ h of liquid * density known but since the h is equal wouldn't it cancel out and the density of the liquid =...

Homework Statement A cube of wood, of mass 0.50 kg and side length 10.80 cm, is floating in a beaker containing alcohol, as shown. a) What is the density of the wood? b) Ifthe wood is exactly half submerged, find the density ofthe alcohol Homework Equations not sure how to go about to...

so the k will still work plugging into second E=K*A^2 with the new A, and thank you did not know most of the equations you posted my prof sucks! got all the hard equations

but would the K apply since i found K using intial energy and initial amplitutde

ahh i see so using the ln equation i can use the ln equation using A1 = 8 cm and A2= 4 cm, then I can figure out T ? then using that constant I can figure out A = (0.08m)*e^(-t/2T) ? with that I can plug into E= KA^s ?

would the time constant be 20 seconds since amplitude is decreased at 20 seconds, since T = m/b how do i calculate for T if the time constant isn't 20 seconds, but I think the time constant is indeed 20 seconds since the amplitude changes at 20 seconds

is it A=Ae^-t/2T where T= M/b ?? I'm not sure what the time constant is in this case ? or would i apply the forumla A = sqrt( xo^2 + (vo/w)^2) ?? in which case i have no idea what the v or the w and the xo is since distance is constantly changing

Homework Statement 3. A damped oscillator's amplitude dec¡eases from 8 cm to 4 cm in 20 seconds, If the intial energy of the oscillator is 64 J, what is the energy âfter 40 seconds? (Recall: E: (l/2)kA2) Homework Equations not sure how to approach the problem The Attempt at a...