Recent content by MATdaveLACK

  1. M

    How Do You Solve the Limit of (5-x) / (3 - sqrt(x^2 - 16)) as x Approaches 5?

    If the limit is zero over non-zero, the limit is just zero. But in this case I'm getting the limit to be 0/0, yeah?
  2. M

    Velocity Time Graphs and Questions

    The velocities of each ball right before they hit the ground will be equal (since when the ball thrown vertically upward comes back down to the point from which it was thrown, it's velocity will be the negative of it's initial velocity, 14.7 m/s. And that is the same velocity the first ball was...
  3. M

    Kinetic Friction and Ropes and Pulleys

    I don't understand why you need to find the coefficient of friction on Block B unless Block B is sliding along something as it falls. As for your question, let's look at Block A. Along the horizontal axis you have Tension pulling the block and friction resisting the block's motion. These two...
  4. M

    A Trigonometric Identity Probelm

    For the second half of your question, sin^2(2x) + cos^2(2x) = 1 (NOT 2) Think about it, sin^2(x) + cos^2(x) = 1 for every value of x. So the range for x is (-infinity, +infinity). And of course 2x falls in that range (every real # falls in that range) This applies as long as the angles are...
  5. M

    A Trigonometric Identity Probelm

    So in your case theta = 2x sin^2(2x)= 1/2(1-cos(4x))
  6. M

    Calculating Deceleration on an Uphill Road

    It looks like in the first scenario friction is providing the decelerating force while in the second scenario both friction and a component of the force of gravity are slowing the car down. You can solve for the coefficient of static friction when the car is simply decelerating on a level rode...
  7. M

    Calculate the coefficient of friction on a rotating carnival ride

    Draw a free body Diagram of a person on the ride. The normal force between the person and the wall of the ride is what is providing the centripetal acceleration (directed towards the center of the ride). Force of Gravity acts down on the person and so friction acts up on the person to keep...
  8. M

    Calculating Roller Coaster Speed at the Bottom of a Dip

    If the passengers feel as if their "weight" increases by 50% at the bottom then that means that the normal force acting up on them is going to be 50% more than the force of gravity acting down on them. You know that the sum of the forces (in this case it would be Normal - Fg) is going to be...
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