Recent content by Math Man900

Nevermind. there are 3 ways to get 1 green person (1st,2nd, or 3rd) which means P( s ) = 3*92/975. and when you work out P( f ) you find the odds are: 92/233. QED. thanks

Homework Statement Of 27 students in a class, 11 have blue eyes, 13 have brown eyes, 3 have green eyes. If 3 students are chosen at random what are the odds of the following occurring? Only 1 has green eyes.Homework Equations Odds = P( s )/P( f ) = P( s )/( 1 - P( s )) Probability success = P(...

when i graphed it, i found the answer to be infinity - infinity*i or (1-i)*infinity none of those answer sound like what a teacher would be looking for, so i would guess the answer is either "limit does not exsist" or you copied the problem wrong

For the 3rd one, an educated guess and check will suffice. |2x|>|5-2x| 2|x|>2|(5-2x)/2| |x|>|5/2-x| If we guess x<0, you can see the equation becomes -x>5/2-x now add x to each side 0>5/2 This is NEVER true, which means that x must be greater than 0. Now if we try x>5/2 our...

You were very close in this one! when u plugged in x=4 and x=-1, you found the bounds of what x can or cannot be. All you need to do is try 3 situations. x<-1 , -1<x<4 , 4<x. If you try the numbers x=-2,1,5 you find the the statement becomes False,False,True that means that the correct answer...

The first one is pretty interesting. first u simply subtract "x" from each side to get (x+4)/(x-2)-x<0 now, to find a common denominator ((x+4)-x(x-2))/(x-2)<0 now, you CANT multiply each side by "x-2" because u don't know if x>2 or x<2 yet. Instead, just simplify some more...

No, because then "e" could equal to Zero.

Ill prove it for ya! Lets say that we have some variable called "y" and let's set it equal to (1+x)^(1/x). so far we have: y=(1+x)^(1/x) now let's take the natural log of each side to obtain Ln(y)=Ln((1+x)^(1/x)) now, we can pull out the "1/x" term in front of the "Ln(" [because...