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math_addict
Recent content by math_addict
M
Hi how to solve? y(y-2x(y'))^3=(y')^2
Thanks, Coomast, for help.
math_addict
Post #7
Mar 13, 2009
Forum:
Differential Equations
M
Solving a Third Order Differential Equation with Initial Conditions
I'm interested in solving this 3rd order DE y'''=3*y*y' with conds y(0)=-2, y'(0)=0, y''(0)=4,5. Thanks for any ideas.. I've the right solution, but the problem is how to achieve it.
math_addict
Thread
Mar 13, 2009
Replies: 2
Forum:
Calculus and Beyond Homework Help
M
Hi how to solve? y(y-2x(y'))^3=(y')^2
The right solutions are y^2=2*(C^3)*x + C^2 and 27*(x^2)*(y^2)=1. Hmm.. Lagrange method doesn't fit properly here
math_addict
Post #5
Mar 11, 2009
Forum:
Differential Equations
M
Hi how to solve? y(y-2x(y'))^3=(y')^2
I tried this way, but it didn't give me any positive result. Moreover even Maple can't solve it exact.. it gives me huge expression..
math_addict
Post #3
Mar 11, 2009
Forum:
Differential Equations
M
Hi how to solve? y(y-2x(y'))^3=(y')^2
Hello Everybody! Have any suggestions how to solve this differential equation, I haven't.. :( y(y-2x(y'))^3=(y')^2
math_addict
Thread
Mar 11, 2009
Tags
Hi
Replies: 6
Forum:
Differential Equations
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