Recent content by math_student03

ok the original function was: y= (x+1)^{1/3} (x^2-x-6) i then got dy/dx= (1/3)(2x+1)^{-2/3}(2)(x^2-x-6) + (2x-1)(2x+1)^{1/3} now here is my dy/dx , from here would i common factor out the (2x+1)^{-2/3} or just put it right to the bottom and get the demon. on one part and set that...

ok so basically for my second line i was only missing a 2 for dsin(2x)/dx and dcos(2x)/dx then i can go ahead and simplift using tri propertys? did i mix something up cause i don't see any that are obvious and secondly, did anyone check out the second question i had on that page, did i do the...

when the denom = 0? .. but there isn't one, or should i transfer the - exponents to the botton and create one?

Hey guys, really stuck on this problem, thanks for the help ! Question: Find the values of x at which the slope of the tangent line to the curve defined by y=(x+1)1/3(x2-x-6) is: a) Undefined / vertical b) horizontal Answer / Attempted answer Firstly I took the derivative...

Hey guys having major trouble with these 2 questions, i have a screen shot of the questions and my work , much easier to understand then me typing it in here. thanks soo much for helping ! http://img204.imageshack.us/my.php?image=img050lc1.jpg

any1 got anything else that can assist me here, I am struggling.

so what you are saying is to just graph it, then it will show we 2 equations where Z is < and > then y^2 - 6 / y-1 .. then what do i do with these to solve the equation?

for3 you use limit, so what does it do when x approaches + - infinity. so, you would get it down to= y^2 -6/y -1 -z then divide each by y^2 = 1- 6/y^3 - 1/y^2 - z/y^2 so when x approaches + - infiinity the limit is 1. hmm never thought of using the y-z plane

and i forget, how would i solve for the interval? and would it have 2?

the question was just given to me like this .. I am going to assume it is for real numbers.

how can we solve anything, or find the intervals with 2 unknowns? .. we don't have 2 solutios 2 unknowns, so I am kinda lost, i don't think i can graph it either with all 2 unknowns.. still need a bit more guidance sry, I am really lost with this one.

hey here is my questions: Find all y satisfying the inequality z<y^2-6/y-1 problem is i do not know where to being, considering there is 2 unknowns. And the top doesn't break down which could simplify the question. Could someone help me out or help me start this question off? thank you.

hey thanks for the help, so for the first one after its broken into 2 parts 7u+2<0 and 7u+2>=0 we would just isolate for u and get 2 solutions? u<7/2 and u>=7/2 ? and for the second one, since B<=0 won't hold and 2 isn't greater then 9 is there no real solutions?

hey guys, tried these problem for a bit but do not think I am on the right track, could someone help me get a lift off with these peoblems, thanks ! the first question: Find all u satisfying the equation u+2=|7u+2|/4+u for this one i have tried to isolate u, then sub it into the quad...

hey guys, tried these problem for awhile and can't get them. Hope i can get some help :) it would be greately aprieciated! the first question: Find all u satisfying the equation u+2=|7u+2|/4+u And the second question is: Find all t satisfying the inequality (2t+6)^1/2 >(or equal to)...