Recent content by Mator

Ok, thanks Kurtz. Will do.Edit: Turns out we went over this stuff during lecture today. I guess I was trying to do the homework before knowing how to do the problems. Anywho, given what I've learned in lecture this should be pretty easy now. Just have to generalize stuff a little bit more...

Ok I'm not sure if I entirely understood your response. I think you're saying to do this: \frac{f(x)}{f''(x)} = 9\frac{g(t)}{g''(t)} I don't see how this does anything to help me solve the equation or show anything about constants, it seems trivial. *does some work* Hmmm... I...

Homework Statement Hopefully no one will mind me posting this as an image. But here it is in tex: Using separation of variables, find the function u(x,t), defined for 0\leq x\leq 4\pi and t\geq 0, which satisfies the following conditions: \frac{\partial^2 u}{\partial...

I'm totally making this up, and it's probably entirely wrong, but it's an interesting idea. Perhaps the warping of spacetime causes this attraction due to a different phenomenon... When I think about the warping of spacetime I note that the surface area of a warped region of space time is...

I understand that you had good intentions, almost all people do, your manner just came across to me in a way that was negative and nit-picking, along with a lot of other pretty words. I'm not here to argue with you, so I'm not going to attempt to dismantle your position any further. I...

No, I was fine with you pointing out that I made a minor oversight on a tiny insignificant (yes, insignificant because I provided a diagram and because I made the problem) detail that I missed. I wasn't fine with you repeating it over and over, bloating the minor oversight out of proportions...

Oh well excuuuuuuse me for not making the problem ABSOLUTELY PERFECT. I added a friggin' diagram so did you really have to point out that tiny insignificant error in the problem? I wrote this myself, and it's the first problem I've ever written and it's nothing like what I'm learning in...

The equation for the wall would be y = -2.8x then, which it wasn't given as. Though I never considered that possibility because I made the problem myself. It was describing something I observed (as stated before). I might post a link to a video because it's hard to explain (if any is curious...

Thank you so much for you fast and detailed response! Ok, let's do this. 2.8x = 2 + v*sin(35)*t - (1/2)*g*t2 t = (x - 8)/(v*cos(35)) 2.8x = 2 + ((v*sin(35))(x - x0))/(v*cos(35)) - (1/2)*g*((x - x0)/(v*cos(35)))2 2.8x = 2 + tan(35)(x - x0) - (1/2)*g*((x - x0)/(v*cos(35)))2 ok g2g...

NOTICE: THIS IS NOT AN ACTUAL HOMEWORK PROBLEM. Homework Statement A projectile is launched from a hill 2m high 8m away from the base of a slanted wall at a velocity v at an angle of 35 degrees from the horizontal. The equation of the slanted wall is y = 2.8x. The slanted wall is 20m high...