Recent content by matt3D

Thanks for all the help!

Oh, I'm sorry, I forgot that the question stated that at t=0, \omega_{i}=2.59rad/s

You can use the period of oscillation: T=2\pi\sqrt{\frac{m}{k}} then put what you found for the period in this equation: f=\frac{1}{T}

Sure, I did this: Angular speed at 2s: \omega= \omega_{i}+\alpha t \Rightarrow 2.59 rad/s + (3.71 rad/s2)(2.00 s)=10.01 rad/s Then the change in t is 4.25s so: \Delta\theta=10.01rad/s(4.25s)+\frac{1}{2}(3.71rad/s^{2})(4.25s)^{ 2}=76.0484 rads Regards, Matthew

Oops, yep, I didn't correctly enter the equations. Thanks willem2, I didn't know I needed the change in t for the second equation. I got 76.0484 rads for the angular rotation between t=2s and t=6.25s.

Homework Statement A wheel rotates with a constant angular acceleration of 3.71 rad/s2. what angle does the wheel rotate between t = 2.00 s and t = 6.25 s? Homework Equations \omega=\omega_{i}+\frac{1}{2}\alpha t^{2} Δθ = θf - θi = ωit + αt2 The Attempt at a Solution I found...

Hey NoUse, why is it that when you add .0, or even . in front of f in the 2nd to last printf statement it removes the 0's after the decimal place for each number? I noticed that if you take out the .0, the output will be 0.000000, 1.000000, etc. And if you add the . or .0 before f it will just...