Wheel rotation, constant acceleration

[matt3D]

Homework Statement

A wheel rotates with a constant angular acceleration of 3.71 rad/s2.
what angle does the wheel rotate between t = 2.00 s and t = 6.25 s?

Homework Equations

\omega=\omega_{i}+\frac{1}{2}\alpha t^{2}
Δθ = θf - θi = ωit + αt2

The Attempt at a Solution

I found the angular speed at 2 seconds which is 10.01 rad/s.
Then I use the second equation:
\Delta\theta=10.01(6.25)+\frac{1}{2}(3.71)(6.25)^{2}=135.023 rads
I can't get the correct answer. What am I doing wrong?
Thanks,
Matthew

 

[willem2]

The first equation you give is incorrect. It should be \omega = \omega_i + \alpha t, so your angular speed at 2 seconds is wrong.

The second equation should have \Delta t in it instead of t, and also (1/2) inf front of the \alpha

 

[matt3D]

Oops, yep, I didn't correctly enter the equations. Thanks willem2, I didn't know I needed the change in t for the second equation. I got 76.0484 rads for the angular rotation between t=2s and t=6.25s.

 

[rl.bhat]

Will you please show your calculations?

 

[willem2]

Will you please show your calculations?

because your answer is unfortunately still wrong.

 

[matt3D]

Sure, I did this:
Angular speed at 2s:
\omega= \omega_{i}+\alpha t \Rightarrow 2.59 rad/s + (3.71 rad/s2)(2.00 s)=10.01 rad/s
Then the change in t is 4.25s so:
\Delta\theta=10.01rad/s(4.25s)+\frac{1}{2}(3.71rad/s^{2})(4.25s)^{ 2}=76.0484 rads
Regards,
Matthew

 

[rl.bhat]

From where did you get ωi = 2.59 rad/s?

 

[matt3D]

From where did you get ωi = 2.59 rad/s?

Oh, I'm sorry, I forgot that the question stated that at t=0, \omega_{i}=2.59rad/s

 

[rl.bhat]

Then your answer is correct.

 

[matt3D]

Thanks for all the help!