The attempt I have done:
E = σ/2εo
The force per unit area on sheet I due to sheet II is:
F = q’E = σ’AE => F/A = σ’E = σ’(σ/2εo) = 3.3x10^-9(7.9x10^-9)/2*8.85x10^-12
F/A = 1.47x10^-6 N/m²
or
FI/A = -σσ’/εo= (3.26x10^-6),
FII/A = -σσ’/εo + σσ”/εo
FIII/A = σ’σ”/εo...
Three large but thin charged sheets are parallel to each other as shown in the figure . Sheet I has a total surface charge density of 7.9 nC/m^2, sheet II a charge of -3.3 nC/m^2, and sheet III a charge of 5.4 nC/m^2.
Figure:
----------------(I)
----------------(II)----------------(III)...