Recent content by Maxx573

  1. M

    Finding the Amplitude of a spring (Simple Harmonic Motion)

    Oh right. Amplitude is measured from the center of the oscillation to the highest (or lowest) point. So A = \frac{x}{2} \approx 0.103m Thanks a ton :)
  2. M

    Finding the Amplitude of a spring (Simple Harmonic Motion)

    Ah, I think I've got it now. So for the system's initial energy: K = 0 (everything is at rest) U_{spring} = \frac{1}{2}(19 N/m)(0)^2 = 0 (the initial position is 0) U_{gravitational} = (0.2 kg)(9.8 \frac{m}{s^2})(x) (for this problem, I will refer to the lowest point as h=0, so initially h=x)...
  3. M

    Finding the Amplitude of a spring (Simple Harmonic Motion)

    Looking at the conservation of energy: K = \frac{1}{2} kA^2\sin^2(\omega_0 t+\phi) = \frac{1}{2}mv^2 U = \frac{1}{2} kA^2\cos^2(\omega_0 t+\phi) = \frac{1}{2}kx^2 E = \frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2}kx^2 OK, obviously something here should help me, but I just keep...
  4. M

    Finding the Amplitude of a spring (Simple Harmonic Motion)

    [SOLVED] Finding the Amplitude of a spring (Simple Harmonic Motion) First post here at PF, so forgive me if I make a faux pas. I'm trying to study for an upcoming Physics test and I'm having a bit of trouble with this. Homework Statement A massless spring with spring constant 19 N/m hangs...
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