Recent content by MechTech

You are forgetting you negative sign. A = -9.8

From the problem we can assume that at t=0 the Y position is 12m. The last line ask us to solve from is 3/4 of Y or 0.75*12. Thus your equation for Y should look as follows: 0.75 *12 = 12 + 4* sin(42)*t - 9.8/2*t^2

y_0 is 12 not zero. Y should be 3/4

Try redrawing the circuit with a straight center wire.

Remember that the generic quadratic eq is ax^2+bx+c. You should get a positive number

Think variable. Both functions are dependant on time.

Try redrawing the circuit

You are on the right track with your attempt but you need to find a relationship between the two equations. (HINT: What do the x position and Y position equations have in common)

They are all elective courses. Thanks for your input

I am a rising senior Physics Major who needs one more class to meet the credit hour requirement to keep my scholarship. These are the class that fit into my schedule that my adviser told me to look at: Intro to Software Engineering - really just advanced C++, UML use, memory management, and...

try negative.33 and negative .3 since I would consider west negative x

Oh and here is a link to superpostion. It the pretty much they way you add vectors. http://en.wikipedia.org/wiki/Superposition_principle

You are on the right path. The cos(0)*.33=.33 that gives you the x component of V1. Sin(0)*.33 gives you the y component of V1. Now take the magnutiude of V2 (.3) and break it down into its X & Y component using -28 degrees (its negative because it south aka below the x axis). The add the X...

Use superpostion. And ad the vectors up. One vector has a magnutiude of .33m/s @ 0 degrees. The second is the wind blowing on the boat then use your arctan to find the angle

1. Collars A & B are connected by a 525-mm long wire and can slide freely on frictionless rods. If force P= (341 N)j is applied to collar A determine the tension of the wire when y=155mm and the magnitude of force Q(which is along the z axis) to maintain equilibrium 2. Homework Equations...