Meden Agan's latest activity
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MMeden Agan reacted to robphy's post in the thread Prove that the integral is equal to ##\pi^2/8## with
Like.
Possibly helpful: $$\frac{\left(\left(\cos x\right)^{2}-\left(\sin x\right)^{2}\sqrt{9-16\left(\sin x\right)^{2}}\right)}{1-\left(\tan... -
MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
I thought about Feynman, but haven't looked deeper into it. My integral is ##\displaystyle{\int_0^a \dfrac{\alpha...
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.The most beautiful form into which we can convert the original integral, according to the picture, is: $$2\int\limits_{0}^{\arcsin...
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MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
See my post #69. And I already posted it a couple of posts before. The expression under the root is ##1+8\cos(2x)## which, together...
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MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
Not really. I am at $$ I=-2\int_{\alpha=0}^{\alpha=a}\dfrac{\alpha\cdot...
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.@fresh_42 Anything new on this beast of an integral? Yesterday I tried to come up with something, but it's only a remark and can't be...
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.I totally agree. That is actually what I was going to say to you.
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MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
I'm afraid I have to agree. Especially, as all the negative roots and singularities haven't even been addressed. I don't think I'll...
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.Mhm. This looks awful. What shall we do?
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MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
The logarithm was obtained from WA. The entire calculation will follow. I think I made an error. Let me check this first.
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.All correct, as far as I'm concerned. Previously, I got confused because I had the variables ##y## and ##z## interchanged. Now, do you...
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MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
I made a mistake and corrected it. That simplifies the formulas a bit. Integration by parts with ##\operatorname{arsinh}## has always...
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MMeden Agan reacted to fresh_42's post in the thread Prove that the integral is equal to ##\pi^2/8## with Like.
Ignoring the singularities and without a good idea to solve the remaining integral, I arrived at: \begin{align*}...
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.How did you obtain that?
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MMeden Agan replied to the thread Prove that the integral is equal to ##\pi^2/8##.Does that simplify anything? I have the feeling we are left with the same old disgusting polynomials.