Recent content by MegaFlyman

Glad to hear that there is a solution. Since this thread is no longer in the schoolwork forum, would you be more forthcoming with the solution.

I'm not seeing anywhere to go after that either. But thanks for the input.

The original diff eq is dx/dy = b(a-x)^1/2 - c(a-x)^1/2 * (x-d)^3/2 Separating variables results in my original posted equation dy = dx/((a-x)^1/2 * (b-c(x-d)^3/2)) I have tried the substitution, u = (a-x)^1/2, x = a-u^2, dx = -2udu. Which results in dy = -2dx/(b-c((-u^2+a)-d)^3/2) Any...

I've separated the variables of this differential equation and end up with dx/((a-x)^(1/2)*(b-c(x-d)^3/2)). I've tried finding the integral of this with non-trig substitution methods but cannot solve it. Any help would be appreciated.