Recent content by MeKnos

I think I got it, but I just want to confirm the answer. Ptot= (Xa)Px + (1-Xa)Py. 760 = (Xa)900 + 600 - (Xa)600 760 - 600 = 160 = 300(Xa) Xa = 160/300 = 53.33%?

this problem should be simple, but i must be doing it wrong. At 250 degrees Celsius, a certain liquid X has a vapor pressure of 900 mm Hg and a second liquid Y has a pressure of 600 mm Hg. What is the minimum mole fraction of X necessary for the mixture to boil at this temperature (assume...

nevermind, i figured it out by myself

Carbon 13

Anyone?

Homework Statement Calculate the binding energy of a neutron in 13-C. Homework Equations mass defect= (Z*mp) + (N*mn) - (mc13) B = mass defect * conversion factor B/(Z+N) = Binding Energy per Neutron I wasn't given any values for the numbers, so I wiki'd them. The Attempt at a...

Anyone?

Unfortunately no. I looked at other similar problems, but they all had the process I'm doing, but I couldn't compare answers.

Isn't B/T = 8.15e-3 Tesla per second? If not, what do I do in that case.

Homework Statement A 21.8 cm diameter coil consists of 18 turns of circular copper wire 1.70 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.15E-3 T/s. Determine the current in the loop. Homework Equations V=IR V=B/T * A * N...

Thanks. Your right. Before my first post, I put 5.06e-6 C as the answer, but that was wrong. Turns out that the answer was -5.06e-6 C, which makes sense now. Thanks again.

When the switch is open, the charge Q is constant (3.38e-6 C) for both plates. When the switch closes, the charge Q1 is 6.76e-6 C and Q2 is 1.68e-6 C. I'm confused on how you find what B actually is, because you don't have a capacitance for that point. I know the voltage difference before the...

Okay, so I did some reading, but I still didn't get the answer. I know that when the switch is open, the charge on both C1 and C2 is the same (3.38 micro C). But after the switch is closed, the charge on C1 becomes (6.75 microC) to account for the same potential drop, and the charge on C2...

Homework Statement Two resistors, R1 = 8.00 Ω and R2 = 4.00 Ω and two uncharged capacitors, C1 = 0.480 μF and C2 = 0.240 μF are arranged as shown in the figure below. With a potential difference of 21.1 V across the combination, what is the potential at point a with S open? (Let V = 0 at the...

101300 (400) / 300 = P2 = 135093 135093 Pa x (.20^2) x 6 = 32422 N and the other way 135093 Pa (.2^2) = 5403 N neither worked