ok... so since I cube the radius, I multiply the % error by 3...
ah. and that gives me 9%.
You are a genius. Why must physics profs supply us with pages and pages of calculations when you can solve a problem like THAT instead...
Thanks :)
hi, I'm attempting a physics problem... it is:
What, roughly, is the percent uncertainty in the volume of a spherical beach ball whose radius is r= 2.86 plus or minus 0.09 m.
Now, I tried to find the percent uncertainty by just doing .09/2.86, but I'm assuming I need to do something with the...