Recent content by MelodyE427

Finally will the force be negative because of the negative charge of the electron? Thanks so much for all your help!

How would I go about finding c?

Is the value for the Ey the same as Ex?

I found Ex by doing E1x=E1cos(44.97) and E2x=E2cos(44.97). I found E1x=1590.05 N/C and E2x=795.05 N/C. So adding those together Ex=2385.08 N/C. Is this correct?

The 49.97 was actually 44.97, i mistakenly typed it. I got from taking the inverse sin of (2/2.81). How would I go about calculating Ex then?

Problem: Charges are located in a gridline figure. The figure has these points: (-0.2m,0.3m) -2 microC, (-0.2m, 0m) +2 microC, (-0.2m,-0.3m) -2 microC, (0.2m,0.3m) +2 microC, (0.2m,0) +2 microC, and (0.2m, -0.3m) +2 microC. a) Calculate x and y components of the electric field at the origin...

Problem: a) 2 charges are located on the y-axis at positions +2 m (-2 microC) and -2 m (-1 microC) respectively. No other charges are present. Each grid is 1 meter. Compute the x and y components of the electric field at the point indicated at the position x = +2 m. Give 2 answers, Ex and Ey...