Recent content by melpomenne

(P cos 30 x 1.6) = (1000 cos 30 x 0.7) + (1000 sin 30 x 0.8) P = 726 N! Wheee! At last!.. .. thanks a lot for the walk through! Ah I'm not really a lumiere when it comes to mechanics.. You're an Ace!

Attempting a moment balance about far right corner :p (P cos 30 x 1.6) = (1000 cos 30 x 0.7) + ( P sin 30 x 0.7) + ( 1000 sin 30 x 0.8) P = 971 N .. doesn't sound right

Ah i give up.. Thanks for your kind help sir :)

Thanks loads! You saved my day ;) OOps now P is coming to 878 N :s

Hiya! Thanks for replying.. I found P to be 697 N.. which does not coincide with that of the book.. its stressing me out :s

Alright will do that... ∑V = 0 R = 1000 cos 30 + P sin 30 = 866 + 0.5 P F = µR = 0.2 ( 866 + 0.5P) = 173.2 + 0.1P ∑H = 0 P cos 30 = F + 1000 sin 30 = 173.2 + 0.1P + 500 P = 673.1/(0.1 + cos 30) = 697N

Hiya! Thanks for replying.. I found P to be 697 N.. which does not coincide with that of the book.. its stressing me out :s

Hiya! Thanks for replying.. According to the way I've worked it out... P comes out to be 697 N.. while the book's answer is 726 N.. this is stressing me out.. I can't figure out where's the mistake.. For the toppling bit, i guess i'll have to do a moment balance about the corner.. and if P <...

1. A uniformly loaded crate of weight 1000N is held at rest on an inclined place. A gradually increasing force P is applied horizontally as shown. If coefficient of friction, u, = 0.2, determine whether the crate first slides or topples and the least force required I am unable to find the least...