Recent content by Memorical

So after more asking around, someone's presented to me the idea that maximum velocity would be the same for acceleration and deceleration which is pretty obvious, but I didn't think to include this in the equation. Is this what you're getting at? So therefore using ##v = at##: ##a_1 t_1 = a_2...

It does indeed seem wrong. So this is what I've done to prove this wrong: Using ##D = \frac{at^2}{ 2}## and: ## a_1 = a_2 ##, so therefore: ##t_1 = t_2 ## and ##d_1 = d_2## ##T = 2 * t_1##, and therefore ##t_1 = \frac{T}{2}## ##D = 2 * d_1## ##D = at_1^2## ##= a (\frac{T}{2}^2)## ##=...

Fair. The wording could do with changing. Basically, I've badly implied that the reason why we're not coasting at a fixed speed is because the traversal needs to be done within the fastest time possible.

Note: Maths has always been kinda a weak point for me in school. Anyway. From hereon I'm going to talk about this in the context of a train for simplicity, even though this is actually needed for an entirely different context - but I don't think this is relevant for the problem. In terms of my...