Recent content by merceb49

i thank you all for the help, i just don't understand this at all. thank you for the time

i was keying it incorrectly, bloodthunder your correct. thank you for all the help on this problem

oh ok, and S is representing? physics is not my calling...

yeah I am trying to answer the first question, and i thank you for coping with my confusion... i understand the second question, i have to find how long it took to find the velocity but i still don't think .5 is the correct time

sqrt of 2(1.325)/9.8=t=.5=fast?

with that i get .3 and .9. i don't understand how trig will lead me to the height when all i have to measure with is a velocity

with that formula i got 0.3, assuming i did it correctly (t = sqrt of 2(.425)/9.8) Is that not a ridiculous number?

using trig gives me 24.5 and that is a velocity, not a measure of height. I would have plugged into the appropriate formulas, the only problem is I do not know any necessary formulas. could i get some help with that?

wow I'm stupid. but i tried this all .5(9.8)t^2=1.325 and I got around 0.5. And this is still incorrect, should I not use the distance it fell horizontally or should I add both of the distances together?

So i do not have the time, or the acceleration. i can't calculate the acceleration because i don't have the mass of the car. I understand how to get the speed but I don't have the time so I don't know how to solve it. How can I find the acceleration?

A toy car runs off the edge of a table that is 1.325 m high. The car lands 0.425 m from the base of the table. How long did it take for the car to fall off the table? How fast was the car going when it fell off the table? and An arrow is shot at 30.0° above the horizontal. Its initial...

A toy car runs off the edge of a table that is 1.325 m high. The car lands 0.425 m from the base of the table. How long did it take to hit the ground? How fast was the car going? My tutor even had trouble with this, without a speed this is no solvable, at least to me. Suggestions on...

thank you so much.

thank you for the link, but none of those equations work, there is no time involved in the situation. Are there any other ways, I'm looking for how many meters it will take for the car going 45m/s to stop at the constant rate of -11m/s squared anything else, please?

ok well i do not know what type of formula, how do i get it?