Recent content by michael page

  1. M

    Pin in Double Shear (Mechanics of Materials)

    Thanks. It makes sense to me that both lug's strains can't be known simultaneously without more information. So I set the left one equal to zero. I also read into the next chapter and I am confident this is the method he wanted us to take (in hindsight).
  2. M

    Pin in Double Shear (Mechanics of Materials)

    I could have drawn it better but I sketched it in like 2 mins. The ends of the bar go on indefinitely on my handout, on both sides. They also show a top view where it can be seen that each lug has same width but it's not given a variable name so it's not something to really consider I don't...
  3. M

    Pin in Double Shear (Mechanics of Materials)

    There's also nothing to say from the diagram that they aren't both fixed to the same thing. Unless you mean a force-couple, torsion was not covered yet in any section of the book. If you could show me something with a force-couple I'm 100% open to looking into that.
  4. M

    Pin in Double Shear (Mechanics of Materials)

    I guess this will have to work. I did what you said. w and E cancelled, you generate the second equation, has to be it am I right??! Thank you, Michael
  5. M

    Pin in Double Shear (Mechanics of Materials)

    They all have the same width. It's not shown as a variable though. If kL = AL * EL / LL for the single element on the left what's the right hand side of this equation? Like how do you superimpose the two stiffnesses in parallel like that again, for the right two bars?
  6. M

    Pin in Double Shear (Mechanics of Materials)

    What if I just said the deflection of the right is the opposite of the deflection of the left would that get me anywhere?
  7. M

    Pin in Double Shear (Mechanics of Materials)

    It's not a beam there are no fixed ends.
  8. M

    Pin in Double Shear (Mechanics of Materials)

    Ok the hint says "Stiffness governs distribution of load". I put everything in terms of distributed loads, w. Based on area of rectangles I tried to say: since t2 = 1.24*t1 w2 = 1.24*w1 But then when I solve for w1 and w2 from this method they don't add up to 10,000 (upon converting back...
  9. M

    Mechanics of materials: Statically Indeterminate member

    Thanks, Chestermiller, https://www.physicsforums.com/threads/pin-in-double-shear-mechanics-of-materials.943188/ This is the new link. Any advice is appreciated. Michael
  10. M

    Pin in Double Shear (Mechanics of Materials)

    Homework Statement Knowing the left lug is carrying 10,000 lbs, determine the loads P1 and P2 in the lugs on the opposite side of the pin. Homework Equations Force Balance (ΣF=0) Another equation needed The Attempt at a Solution 10000 = P1 + P2 This is where I need another equation to...
  11. M

    Mechanics of materials: Statically Indeterminate member

    I feel like this one is in the same category. I have only the data shown, no E, no d. I need to find the P1, P2 loads purely from stiffness considerations. Obviously P1 + P2 = 10000 but what outside equation or field of knowledge can I use to get a second equation from which I can help to solve...
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