Recent content by Michaelh926

:) now i understand it. thank you to everyone that helped

so is it √14/sinθ=5/cosθ tanθ=√14/5 θ=arctan(√14/5)?

Sorry, forgot to put the exponents in. So will this be what it comes to... sinθ=sqrt(14)/5 then solve for theta?

so, the value of |u x v|=sqrt(2^+3^+1^)? then substitute it so it will be |sqrt(2^+3^+1^)|=|u||v|sinθ?

so, the value of |u x v|=sqrt(2^+3^+1^)? then substitute it so it will be |sqrt(2^+3^+1^)|=|u||v|sinθ?

Question: Let u·v = 5 and u×v = 2i+3j+k. Determine the angle (in degrees to one decimal place) between the two vectors. Im not sure on what to do with the equation given since other examples that were done i was given separate equations for u and v We were told this formula will be used but...