Recent content by MichaelRocke

Brilliant, thank you for your advice here. I have plenty of more exercises to go and starting to tear through them at a much faster pace.

Thank you Merlin3189 for your solution too. I like the idea, very elegant too. For my approach, I tried to reach the end of $$\sin\theta\tan\theta$$ without using it in any steps (if that makes sense), I don't know if I was being overly strict on myself?

Thank you! I literally stuck at it for a few minutes more and learned how to fiddle with the fractions so it cancels \begin{align*} \frac{\sin \theta + \tan \theta}{\csc \theta + \cot \theta} = \\ \frac{\sin \theta + \frac{\sin \theta} {\cos \theta} }{\frac{1}{\sin \theta} + \frac{\cos...

Thank you for your replies! I have gotten so far\begin{align*} \frac{\sin \theta + \tan \theta}{\csc \theta + \cot \theta} = \\ \frac{\sin \theta + \frac{\sin \theta} {\cos \theta} }{\frac{1}{\sin \theta} + \frac{\cos \theta}{\sin \theta}} = \\ \frac{\sin \theta (1 + \frac{1} {\cos \theta})...

Hey there! I'm Michael, a software developer in the UK. I am currently on the journey to teach myself mathematics. I haven't studied maths since College/A Levels, and have forgotten so much of it. I'd like to get back into mathematics to further advance my computer science, physics and biology...

My latest attempt \begin{align*} \frac{\sin \theta + \tan \theta}{\csc \theta + \cot \theta} = \\ \frac{\sin \theta + \tan \theta}{\csc \theta + \cot \theta} \cdot \frac{\csc \theta - \cot \theta}{\csc \theta - \cot \theta} =\\ \frac{\sin \theta \csc \theta + \tan\theta \csc \theta - \sin...