Recent content by MicheleC88

However, I think I made the math more complex than necessary: ki - kf = kph = \frac{2π}{λ}\widehat{k}_{ph} (ki - kf) / (size of Brillouin zone) = \frac{2π}{λ}\frac{a}{2π}\widehat{k}_{ph} << 1 \cdot \widehat{k}_{ph} Thanks to all for the reply!

I tried to make the following math. from energy conservation: Eph≈Egap (assuming that initial and final electrons are in proximity of, respectively, the maximum of VB and minimum of CB) We know that kph = ω/c = Eph/(\hbarc) So, from momentum conservation law: |kf - ki | = |kph|≈Egap/(\hbarc)...

So, I think having understood from your words, the key is that the conservation of momentum has to be combined with the conservation of energy?

Hi everybody. I'm new here and, first of all, sorry for my bad english :-D I'm studying photoelectric absorption in semiconductors. The book (and professor too) says that, in the conservation law: ki + kph = kf (where ki and kf are wave vectors of initial and final electron state, and...