Actually, I had a friend help me. Thanks anyways though. It turns out I was forgetting to factor in Fnet (the masses are moving). Fnet would have had me using a formula like this.
m2a = m2g - m1a
And solving from there.
It's very clear I need to remember that T ≠ Fg/2 while it is...
A 1.20kg object is placed on a smoothe level table and is attached to a hanging mass using a light string over frictionless pulley in a Fletcher's trolley arrangement. The 1.20kg object accelerates along the table at 2.31m/s^2 while the hanging object accelerates down at...
Ahh okay, yeah we've done kinematic equations, but I was having a hard time remembering them, and we never referred to SUVAT at all as an acronym. Thanks so much for the help guys, I finally got the right formula for the question:
a = (Vf^2 - Vi^2)/2D
F = 5.26kN
Thanks for helping my...
A 1000kg car is travelling at 27.0 m/s. Determine the force required to stop it in 70.0 m.
The Attempt at a Solution
I attempted to treat this question as if I knew how many seconds it took to stop, and did this:
70.0m / 27.0m/s = 2.59259s
2.59259s / 27.0m/s = 0.096...