Recent content by mikemichiel

thanks pinu

1. Sketch the plane curve represented by the vector-valued function r(t)=cosh ti +sinh tj on the interval 0</(trying to say less then or equal to)t</(also less then or equal to)5. Show that the rectangular equation corresponding to r(t) is the hyperbola x^2-y^2=1. Verify your sketch using a...

thanks!

yes it would be sec^2φ. Then I would square that and it would become secφ then multiply it be the sec^2φ I had for my dy. So I am basically integrating sec^3φ?

so my dy would be sec^2φ. So if i plug that in il get ln |sec x|-ycothφsec^2φ. So would i have to plug in my y=tanφ for my y in front of the cothφ? If not would it just be ln |sec x|-y^2/2cothφsec^2φ?

Hey i have this integral √1+y^2-(cothφ)ydy(with the square root on consisting of 1+y^2. I evaluated it but I just want to you guys to check and see if you think its good. For the radical part I used a trig substitution y=tanφ The integral of tanφ is ln |sec x| And for the (cothφ)y part I...

Im givin these two lines.. L1= x=4+5t y=5+5t z=1-4t L2= x=4+s y=-6+8s z=7-3s What i tried doing was taking the directional vector of both lines <5 5 -4> <1 8 -3>, and crossing them to find the normal vector. I have enough information to find 1 equation of a plane, but how can I find the...