Recent content by Mingsliced

Looks like you've miscalculated: 4189/4620 = 0.9067 0.9067 * 100 = 90.7% Question D was indeed unanswered, it's not exactly explained very clearly. The only advice I was given from my lecturer: "Here we need an equation in which the only variable is the load torque, the other factors...

Homework Statement It is proposed to pump 1500 m3 of a liquid (density 1100 kg m–3) each day through a total head of 10 m (including all losses) by using either a centrifugal pump or a reciprocating pump. The centrifugal pump discharges 2.0 m3 min–1 when driven by an electric motor supplying...

Thanks very much!

Homework Statement This is simply a sanity check concerning the system described and attached. My concerns are detailed within my attempts at the solution. Any guidance will be greatly appreciated! The diagram attached represents a process for which a pump and associated pipe work require to...

Don't worry, I've figured it out. The above post is incorrect anyway. Thanks for the hint :)

By using the angular velocity Wi: input power = Ti * Wi. I'm guessing to get Wi that you divide the output speed by 5, so 300/5 = 60. Then convert to RAD/s to get 6.283 RAD/s. Then placing that into input power formula: 33.58 * 6.283 = 210.98 Watts. Is that correct?

Homework Statement [/B] I've been working my way through the following question but I am a little bit stuck at this part: A gearbox and flywheel are as shown in FIGURE 4. The output shaft rotates in the opposite direction to the input shaft at 5 times its speed. The gearbox has an efficiency...

Thank you, I'm pretty confident I've cracked it now :)

Apologies, I've attached a new image to this post which should hopefully work for you. Regards, Ming

Homework Statement After happily working my way through the earlier parts of this question, I'm pretty much at the end of my tether with the last two parts. Please find the diagram attached: A) Determine the value of the angle θ (measured from vertical) when the angular velocity of link AB a...

Ah excellent, thanks very much!

Ah, I think I can see where I've gone wrong... I was using Q = M * Cp (T2 - T1) and Q = Cv (T2 - T1), but using Q=30kj instead of 20kj. So Cp = 1kj/kg K and Cv = 0.5kj/kg K Therefore R = 0.5kj/kg K Is this correct? Thankyou :) Yes, I believe that it is stated as an ideal gas.

Homework Statement Just want to check that I've used the correct method for this thermodynamics question I've been set. Any clarification would be greatly appreciated. So I have 0.5kg of gas held in a rigid container of volume 0.25m^3 at a temperature of 20°C. 20kJ of heat energy is required...

Thanks :)

Just want to check that I've used the correct method for this thermodynamics question I've been set. Any clarification would be greatly appreciated. So I have a closed system in which a gas is compressed from a pressure of 3 bar absolute to 5 bar absolute. The volume changes from 0.9m^3 to...