Recent content by minidee

yep, the right answer from the machine said the 1.22 x 550 x 10-9/3.1 one was correct? Thanks!

would the theta min from 1.22 x 550 x 10-9 / 3.1mm be the right theta min then? I wuold get L=1660m for this theta min?

i got theta min is 1.774 x 10^-4 from 550x10-9/3.1mm I believe. What's my mistake?

yeah i keep getting thetamin = 0.36/L and answer 2029. what am I doing wrong?

hi there! I'm someone else asking the same question. so is the answer 4f? I don't understand what you mean by extremum and find the values of s and p so that it cannot equal 4f.

I got I_1 = 10^2. What to do next?!

Can the Firecracker Be Heard? Introduction: The decibel scale is logarithmic in intensity: beta = 10log[I/I_0] In this formula, I_0 is a reference intensity. To convert the intensity of sound waves from SI units to dB, I_0 is taken to be 10^{-12}W/m^2. Once you know the intensity of a...

I found help elsewhere. Your way with the K constant is actually quite unnecessary. It's faster to use just V1 and gamma. Thanks for coming back and trying to help I guess.

I'm confused. What have I done wrong with my equation. By the way, I'm a different person asking the same question. :) What is K, the original temperature? And how do you get P, through the p0=t1/v1 equation?

as a continuation of this problem, I tried to solve it by using the equation: v2^(1/3) = [t1*v1^(1/3)]/t2 Found t2 by: po=pf=t1/v1=t2/2v1 2t1v1/v1=t2 2t1=t2 so... i got v2^(1/3) = {[299*(7050cm3 *10-9 m3)^1/3] / 598} v2={0.00958}^3 =8.81 * 10-7 The answer machine says wrong. What did I do...

i've noticed no one has answered yet. I kind of need this by tonight. thanks!

so I'm guessing that A works because the law applies W=Q. B actually works because in the carnot engine cycle, isothermal expansion can be reversed. C, the area represents work. I would say that more work is done on the isobaric. So A and B only is the correct answer. Am I right?

Which of the following statements are true? 1. Heat is converted completely into work during isothermal expansion. 2. Isothermal expansion is reversible under ideal conditions. 3. During the process of isothermal expansion, the gas does more work than during the isobaric expansion...

anyone?

That's the headline in the lab manual! I'm not sure why the absolute matters either! Big Thanks for helping! next time i'll include work.