Recent content by minidee

  1. M

    Resolving pixels on a computer screen

    yep, the right answer from the machine said the 1.22 x 550 x 10-9/3.1 one was correct? Thanks!
  2. M

    Resolving pixels on a computer screen

    would the theta min from 1.22 x 550 x 10-9 / 3.1mm be the right theta min then? I wuold get L=1660m for this theta min?
  3. M

    Resolving pixels on a computer screen

    i got theta min is 1.774 x 10^-4 from 550x10-9/3.1mm I believe. What's my mistake?
  4. M

    Resolving pixels on a computer screen

    yeah i keep getting thetamin = 0.36/L and answer 2029. what am I doing wrong?
  5. M

    Smallest distance between object and image - lens.

    hi there! I'm someone else asking the same question. so is the answer 4f? I don't understand what you mean by extremum and find the values of s and p so that it cannot equal 4f.
  6. M

    Can the Firecracker Be Heard?

    I got I_1 = 10^2. What to do next?!
  7. M

    Can the Firecracker Be Heard?

    Can the Firecracker Be Heard? Introduction: The decibel scale is logarithmic in intensity: beta = 10log[I/I_0] In this formula, I_0 is a reference intensity. To convert the intensity of sound waves from SI units to dB, I_0 is taken to be 10^{-12}W/m^2. Once you know the intensity of a...
  8. M

    Adiabatic expansion of a balloon

    I found help elsewhere. Your way with the K constant is actually quite unnecessary. It's faster to use just V1 and gamma. Thanks for coming back and trying to help I guess.
  9. M

    Adiabatic expansion of a balloon

    I'm confused. What have I done wrong with my equation. By the way, I'm a different person asking the same question. :) What is K, the original temperature? And how do you get P, through the p0=t1/v1 equation?
  10. M

    Adiabatic expansion of a balloon

    as a continuation of this problem, I tried to solve it by using the equation: v2^(1/3) = [t1*v1^(1/3)]/t2 Found t2 by: po=pf=t1/v1=t2/2v1 2t1v1/v1=t2 2t1=t2 so... i got v2^(1/3) = {[299*(7050cm3 *10-9 m3)^1/3] / 598} v2={0.00958}^3 =8.81 * 10-7 The answer machine says wrong. What did I do...
  11. M

    Isothermal Expansion: Work and Heat

    i've noticed no one has answered yet. I kind of need this by tonight. thanks!
  12. M

    Isothermal Expansion: Work and Heat

    so I'm guessing that A works because the law applies W=Q. B actually works because in the carnot engine cycle, isothermal expansion can be reversed. C, the area represents work. I would say that more work is done on the isobaric. So A and B only is the correct answer. Am I right?
  13. M

    Isothermal Expansion: Work and Heat

    Which of the following statements are true? 1. Heat is converted completely into work during isothermal expansion. 2. Isothermal expansion is reversible under ideal conditions. 3. During the process of isothermal expansion, the gas does more work than during the isobaric expansion...
  14. M

    Mechanical Equivalent of Heat

    This lab involves a spool that has a crank on it and also has a string wrapped around it several times with a mass hanging on the edge of the string hanging vertically. 4.)Suppose, the cord where it is attached to the post, is under tension during the experiment. Would this lead to error in...
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