Recent content by mirandab17

Homework Statement The threshold frequency of a metal is 3.184 x 10^14 Hz. If a photon of wavelength 368 nm strikes the surface of the metal, what is the wavelength of the ejected electron? Homework Equations f (frequency) = c/(wavelength) Eincident = Ethreshold + KE E=fv(wavelength)...

The denominator should be (3/7) because it's only involving bag N?

so (2/7)(3/8) / (11/21)?

But it is conditional right? So IF a white ball was picked from bag N, which is 11/21, the probability of transferring a red ball from M to N is... I'm assuming red was picked first here then... so (2/7) and then white (3/8)...?

Okay... I don't understand how P(R1&W2) turned into P(W2/R1) P (R1). Why are you multiplying it?

Bag M contains 5 white balls and 2 red balls. Bag N contains 3 white balls and 4 red balls. a) A ball is randomly selected from Bag M and Placed in Bag N. A ball is then randomly selected from Bag N. What is the probability that the ball selected form Bag N is white? b) If a white...

Bag A contains 5 white balls and 2 green balls. Bag B contains 3 white balls and 4 green balls. A fair die is rolled and if a 1 or a 2 comes up, a ball is randomly selected from Bag A; however, if a 3, 4, 5 or 6 comes up, a ball is randomly selected from Bag B. a) What is the probability of...

An electron moves in a circular orbit of radius r in a magnetic field. The electron moves in a path perpendicular to the magnetic field. If the kinetic energy of the electron is doubled, what is the new radius of its path? What formula would I use to go about this? Is this about mass...

24. A square coil is perpendicular to a uniform magnetic field. Which one of the following would increase the magnetic flux through the coil? A. Decreasing the area of the coil. B. Increasing the number of loops in the coil. C. Removing the coil from the magnetic field. D. Increasing the...

Thanks! Finally get it, awesome.

Is this an exception though? Because there have been so many other scenarios where I haven't had to do this. Why now did we have to add up the potential drops? As in, why didn't the formula work?

Hmm... okay... so what would happen if the internal resistor was on the left hand side? Would there still be two potential drops? I'm just confused because I haven't had to deal with adding up the potential drop across the internal resistor and EMF value itself before in order to find terminal...

Voltage across R2 V = IR = (1)(6) = 6 V Is the voltage across R1 the EMF minus the voltage parallel? So voltage across R1 = 30 - 6 = 24 V? Current through R1 would be I=V/R = 24/4 = 6 A. Oh! And then if there's only 1 A through R2 then there must be 5 A through the wrench due to Kirchoff's...

oooh okay let me do that then...

I don't know how to go about finding the current through the wrench though... especially if it has negligible resistance.