Recent content by MironeDagains

http://www5a.wolframalpha.com/Calculate/MSP/MSP238521i5b83i951f19c3000010ca05be63f0bfc0?MSPStoreType=image/gif&s=10&w=219.&h=85. How do I solve this? I know the answers, as Wolphram Alpha has given me only the answers without any steps to how they derived those answers. I know that sin(x)=√3/2...

When you switch on an electromagnet (who's north pole is pointing to the left), is it the same thing as if you had pushed a permanent magnet to the left? Or to the right? I believe it's to the left. But apparently my textbook thinks it's to the right. Who's correct? Why I'm asking:I've attached...

Yes, they are. What? What's that supposed to mean? I already did the calculations, using my new equations, and got answers that were very close to my teacher's. What are you telling me to change and 're-do'?

Reversed? Well, F1 is pointing to the left and F2 is pointing to the right. As shown in the diagram.

F1 = ##\frac{1.96cos(θ)}{cos(θ)sin(Φ)+sin(θ)cos(Φ)} ##N and F2 = ##\frac{1.96cos(Φ)}{cos(θ)sin(Φ)+sin(θ)cos(Φ)} ##N Correct? My answers are much closer to my teacher's now. Which means it is correct.

Edit: nevermind. There is no time to wait for a reply. Admins, please delete this thread.

But that's exactly the steps taken to solve 2 very similar (practically identical) problems in my physics book?? Look: http://i.imgur.com/nqK5TTY.png what am I missing here? The sum of horizontal forces are equal to zero, and the sum of the vertical forces equal zero. Right?

Homework Statement There's a 200g piece of weight hanging by a string. That string is then split into two strings, each at θ from the horizontal and Φ from the horizontal. These two strings are each connected to force sensors which measure their tension in Newtons. I know how to do this...

Thanks for the help! Note: I just discovered that I broke practically every rule here lol sorry

So... the answer is 2.41N for 60cm? Yes or no? Note: you're not "outright giving a solution", you're simply responding "yes" or "no" in regards to whether or not it is the answer. There is no rule regarding agreeing or disagreeing with a proposed answer. "No" or "yes" aren't against the rules.

Well, obviously Nm=N*m...but i didn't think you'd ask me such an obvious question, so I thought it was more complicated than that. Correct?

Well, using logic: T= [F ] [r ] [sinθ ] T= [Newton] [metres] [nothing] F=Newton Newton/metre=Pa=1kg/metre2 So, therefore, your "Nm = ?*m" statement means that '?'=1kg/m-1 I think...

So, for example 60cm, would be: 1.646=F(1)sin(43) F=2.41N or 2.41Nm-1 ?

Torque/meter=Tm-1 I think.. Edit: I mean, Newtons/meter=Nm-1 I think.. But I know that tension in general in a string is simply Newtons=N

Would it be Tweight + Truler =Fstring(1.00)sin(43)? If so, wouldn't that just give the torque of the string? How then, will I convert that to force in Newtons? Edit: ignore that. I hallucinated and thought the F was a T (lack of sleep). So, that's it? That'll give me the tension in the string...